Understand the idea.
An inverse must be single-valued
A function is one-to-one when distinct allowed inputs always produce distinct outputs. Equivalently, forces . On a graph, every horizontal line meets the curve at most once.
To disprove this property, exhibit one pair of different allowed inputs with the same output. To prove it, use arbitrary inputs or a justified strict-monotonicity argument. Several successful sample comparisons are not a general proof.
The domain controls injectivity
The domain can change the answer. The square function fails to be one-to-one on all real numbers, but it is one-to-one on either or . State the actual domain when making the claim.
A disconnected graph can still be one-to-one. For a reciprocal, negative and positive branches produce different signs of output, so they cannot share an output. The horizontal-line test concerns repeated output values, not whether the curve is connected.
See the method in action.
A failed test
Is one-to-one on the real numbers? Justify your answer.
Worked solution
- 1
Choose two distinct allowed inputs.
A single counterexample pair can refute one-to-one behaviour.
- 2
Compare their outputs.
The two different inputs give exactly the same output.
- 3
Conclude from the repeated output.
Therefore is not one-to-one on the real numbers; the horizontal line meets its graph twice.
No.
An algebraic proof
Is , , one-to-one?
Worked solution
- 1
Start with equal outputs at arbitrary allowed inputs.
The implication must hold for any two inputs in the domain.
- 2
Multiply by the nonzero product.
Both denominators are nonzero, so multiplying and cancelling are valid.
- 3
Conclude injectivity.
Equal outputs can only come from the same input, proving that the reciprocal is one-to-one on its full nonzero domain.
Yes.
Try it yourself.
Check your understanding
Is one-to-one on all real inputs?
Show answer & reasoning
No.
The distinct allowed inputs and both give . This counterexample shows that the absolute-value function is not one-to-one on all real inputs.
Keep practising
6 worksheet questions · 16 marks
Read the questions online
- Is one-to-one on the real numbers? Justify your answer.2 marks
- Show is one-to-one on the real numbers.3 marks
- Is , , one-to-one?3 marks
- Find two distinct inputs with the same output for .3 marks
- Give two maximal intervals on which is one-to-one.3 marks
- Explain why has at most one input for each output.2 marks
Read the worked solutions
Equivalent correct methods earn the corresponding marks. Include units where asked.
- Is one-to-one on the real numbers? Justify your answer.2 marks
Use even though the inputs differ.
No. - Show is one-to-one on the real numbers.3 marks
If , then and .
It is one-to-one. - Is , , one-to-one?3 marks
If for nonzero , multiplying by gives .
Its separated branches do not share any y-value.
Yes. - Find two distinct inputs with the same output for .3 marks
.
Use two different roots.
and both give . - Give two maximal intervals on which is one-to-one.3 marks
The graph is strictly decreasing on the first interval and increasing on the second.
Each restriction passes the horizontal-line test.
and . - Explain why has at most one input for each output.2 marks
For , raising a base greater than 1 to these powers gives .
A horizontal line meets its graph at most once.
It is strictly increasing.
Curriculum reference & lesson scope
SACE Board of South Australia
Stage 2 Specialist functions and sketching graphs. Calculus-based analysis assumes concurrent Methods differentiation; real-polynomial division detail is taught in the separate Real Polynomials chapter.
Official curriculum source ↗