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YEAR 12 · FUNCTIONS AND GRAPH SKETCHING · 22 MIN

One-to-one functions

Decide whether different inputs can produce the same output.

In this lesson

Before you start
  • Year 11 functions and algebra
  • Methods differentiation for stationary-point analysis
01 / LEARN

Understand the idea.

An inverse must be single-valued

A function is one-to-one when distinct allowed inputs always produce distinct outputs. Equivalently, f⁡(a)=f⁡(b) forces a=b. On a graph, every horizontal line meets the curve at most once.

To disprove this property, exhibit one pair of different allowed inputs with the same output. To prove it, use arbitrary inputs or a justified strict-monotonicity argument. Several successful sample comparisons are not a general proof.

The domain controls injectivity

The domain can change the answer. The square function fails to be one-to-one on all real numbers, but it is one-to-one on either [0,∞) or (−∞,0]. State the actual domain when making the claim.

A disconnected graph can still be one-to-one. For a reciprocal, negative and positive branches produce different signs of output, so they cannot share an output. The horizontal-line test concerns repeated output values, not whether the curve is connected.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

A failed test

Is f⁡(x)=x2 one-to-one on the real numbers? Justify your answer.

Worked solution

  1. 1

    Choose two distinct allowed inputs.

    2,−2∈ℝ,2≠−2.

    A single counterexample pair can refute one-to-one behaviour.

  2. 2

    Compare their outputs.

    f⁡(2)=22=4,f⁡(−2)=(−2)2=4.

    The two different inputs give exactly the same output.

  3. 3

    Conclude from the repeated output.

    f⁡(2)=f⁡(−2) with 2≠−2.

    Therefore f⁡(x)=x2 is not one-to-one on the real numbers; the horizontal line y=4 meets its graph twice.

Answer

No.

EXAMPLE 02

An algebraic proof

Is f⁡(x)=1⁢/⁢x, x≠0, one-to-one?

Worked solution

  1. 1

    Start with equal outputs at arbitrary allowed inputs.

    1a=1b,a≠0,b≠0.

    The implication must hold for any two inputs in the domain.

  2. 2

    Multiply by the nonzero product.

    a⁢b(1a)=a⁢b(1b) ⇒ b=a.

    Both denominators are nonzero, so multiplying and cancelling are valid.

  3. 3

    Conclude injectivity.

    f⁡(a)=f⁡(b) ⇒ a=b.

    Equal outputs can only come from the same input, proving that the reciprocal is one-to-one on its full nonzero domain.

Answer

Yes.

03 / YOUR TURN

Try it yourself.

Check your understanding

Is ∣⁢x⁢∣ one-to-one on all real inputs?

Show answer & reasoning

No.

The distinct allowed inputs −2 and 2 both give ∣−2⁢∣=∣2⁢∣=2. This counterexample shows that the absolute-value function is not one-to-one on all real inputs.

Keep practising

6 worksheet questions · 16 marks

Read the questions online
  1. Is f⁡(x)=x2 one-to-one on the real numbers? Justify your answer.
    2 marks
  2. Show f⁡(x)=3⁢x−7 is one-to-one on the real numbers.
    3 marks
  3. Is f⁡(x)=1x, x≠0, one-to-one?
    3 marks
  4. Find two distinct inputs with the same output for f⁡(x)=x3−3⁢x.
    3 marks
  5. Give two maximal intervals on which f⁡(x)=(x−2)2 is one-to-one.
    3 marks
  6. Explain why f⁡(x)=2x has at most one input for each output.
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Is f⁡(x)=x2 one-to-one on the real numbers? Justify your answer.
    2 marks

    Use f⁡(2)=f⁡(−2)=4 even though the inputs differ.

    No.
  2. Show f⁡(x)=3⁢x−7 is one-to-one on the real numbers.
    3 marks

    If 3⁢a−7=3⁢b−7, then 3⁢a=3⁢b and a=b.

    It is one-to-one.
  3. Is f⁡(x)=1x, x≠0, one-to-one?
    3 marks

    If 1a=1b for nonzero a,b, multiplying by a⁢b gives a=b.

    Its separated branches do not share any y-value.

    Yes.
  4. Find two distinct inputs with the same output for f⁡(x)=x3−3⁢x.
    3 marks

    x3−3⁢x=x⁢(x2−3).

    Use two different roots.

    0 and 3 both give 0.
  5. Give two maximal intervals on which f⁡(x)=(x−2)2 is one-to-one.
    3 marks

    The graph is strictly decreasing on the first interval and increasing on the second.

    Each restriction passes the horizontal-line test.

    (−∞,2] and [2,∞).
  6. Explain why f⁡(x)=2x has at most one input for each output.
    2 marks

    For a<b, raising a base greater than 1 to these powers gives 2a<2b.

    A horizontal line meets its graph at most once.

    It is strictly increasing.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 Specialist functions and sketching graphs. Calculus-based analysis assumes concurrent Methods differentiation; real-polynomial division detail is taught in the separate Real Polynomials chapter.

Official curriculum source ↗

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