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YEAR 9 · REAL NUMBERS · 12 MIN

Exact answers versus approximations

Keep root and pi answers exact until the final step, then round to the requested precision.

In this lesson

Before you start
  • Square roots
  • Circle circumference
01 / LEARN

Understand the idea.

Exact values retain all the information

An exact value retains the complete number, even when its decimal expansion never ends. Fractions, roots and multiples of π often give concise exact answers. Leaving 50 unevaluated does not make the answer unfinished.

An approximation trades some precision for a usable measurement. Attach the requested unit and use ≈ when rounding changes the value. Two decimal places means two digits after the decimal point, not two digits in total.

50 cm≈7.07 cm

Round once at the end

Keep an exact expression or the full calculator value until the final step. An early rounded value can introduce error into every later multiplication or division. Evaluate the complete expression before applying the requested rounding.

Exact does not mean irrational: 49=7 exactly. Equally, a finite display for π remains an approximation. Choose = or ≈ by whether the values are identical, rather than by the notation they use.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Exact and measured square sides

A square has area 50 cm2. Give its side exactly and to two decimal places.

Worked solution

  1. 1

    Write the area equation.

    s2=50 cm2

    A square has area equal to the square of its side length.

  2. 2

    Select the positive side length.

    s=50 cm

    A physical side length is positive; the negative algebraic root is not a length.

  3. 3

    Evaluate without rounding early.

    s=7.071067⁢… cm

    The non-terminating decimal represents the same exact positive root.

  4. 4

    Round to two decimal places.

    s≈7.07 cm

    The third decimal digit is 1, so the hundredths digit stays unchanged.

Answer

50 cm≈7.07 cm.

EXAMPLE 02

A circumference involving pi

A circle has radius 3 cm. Give its circumference exactly and to two decimal places.

Worked solution

  1. 1

    Substitute the radius in the circumference formula.

    C=2⁢π⁢r=2⁢π⁢(3) cm

    The circumference is twice pi times the radius.

  2. 2

    Retain the exact circumference.

    C=6⁢π cm

    Keeping pi preserves the exact value.

  3. 3

    Evaluate and round at the end.

    C=18.849555⁢… cm≈18.85 cm

    The third decimal digit is 9, so 18.84 rounds up to 18.85.

Answer

6⁢π cm≈18.85 cm.

03 / YOUR TURN

Try it yourself.

Check your understanding

Which sign belongs between 9 and 3: = or ≈?

Show answer & reasoning

=.

Use =: the principal square root of 9 is exactly 3 because 32=9. No rounding is involved.

Keep practising

6 worksheet questions · 14 marks

Read the questions online
  1. A square has area 23 m2. Write its exact positive side.
    2 marks
  2. Round 23 to two decimal places.
    2 marks
  3. A circle has diameter 7 m. Give its exact circumference.
    2 marks
  4. Round the circumference for diameter 7 m to one decimal place.
    2 marks
  5. A student uses 1.4 for 2 and obtains 102≈14. Find the result to two decimal places without rounding early.
    3 marks
  6. For radius 50 cm compare C=100⁢π with 100⁢(3.14). How much smaller is the second value, to two decimal places?
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. A square has area 23 m2. Write its exact positive side.
    2 marks

    The positive number whose square is 23 is 23.

    23 m.
  2. Round 23 to two decimal places.
    2 marks

    23=4.795831⁢…; the third decimal rounds 4.79 to 4.80.

    4.80.
  3. A circle has diameter 7 m. Give its exact circumference.
    2 marks

    C=π⁢d=7⁢π m.

    7⁢π m.
  4. Round the circumference for diameter 7 m to one decimal place.
    2 marks

    7⁢π=21.991148⁢…, giving 22.0 m.

    22.0 m.
  5. A student uses 1.4 for 2 and obtains 102≈14. Find the result to two decimal places without rounding early.
    3 marks

    102=14.142135⁢….

    Round the complete calculation, not the root alone.

    14.14.
  6. For radius 50 cm compare C=100⁢π with 100⁢(3.14). How much smaller is the second value, to two decimal places?
    3 marks

    100⁢π−314=0.159265⁢… cm.

    0.16 cm smaller.
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Curriculum reference & lesson scope

Australian Curriculum v9 and SA Curriculum Mathematics

Year 9 real-number classification and applications; root bounds and sensible digital approximation. Full surd manipulation is developed in Year 10.

Official curriculum source ↗

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