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YEAR 9 · LINEAR EQUATIONS AND GRAPHS · 15 MIN

Testing parameter changes digitally

Test how changing a line's gradient or intercept affects its graph, using controlled comparisons and supplied values.

In this lesson

Before you start
  • Gradient–intercept form
  • Substitution
  • Plotting points
01 / LEARN

Understand the idea.

Change one thing at a time

The parameters m and c control different features of y=m⁢x+c. Hold one fixed while changing the other, so a change in the graph can be traced to a single cause.

Predict first, then compare equations at matching inputs using a table or graphing tool. Record the axis scale and the parameter changed. Several examples help reveal a pattern; algebra is needed to justify a claim for every input.

Equal-unit Cartesian grid from negative six to eight on both axes, showing the labelled parallel lines y equals two x minus one in gold and y equals two x plus three in sage.
Only the intercept changes
xy = 2x - 1y = 2x + 3
-2-5-1
-1-31
0-13
115
237

Explain the pattern algebraically

Changing only c adds the same amount to every output, producing a vertical shift and equal gradients. Changing only m leaves the point (0,c) fixed, because the m⁢x term vanishes there.

A larger gradient does not always give a higher graph. The sign of x matters when comparing m⁢x. Use an output difference to explain when one rule is higher, or one counterexample to refute an "always" claim.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Predict an intercept change

Compare y=2⁢x−1 with y=2⁢x+3. What changes?

Worked solution

  1. 1

    Compare the gradients.

    m1=2,m2=2

    The coefficient of x is unchanged.

  2. 2

    Subtract outputs at the same input.

    y2−y1=(2⁢x+3)−(2⁢x−1)=4

    The x-terms cancel for every real input, not just the values in a table.

  3. 3

    Describe the resulting shift.

    y2=y1+4

    Every point moves up 4 units, so the two distinct lines remain parallel.

Answer

A vertical shift up 4 units; the gradient is unchanged.

EXAMPLE 02

Test a tempting claim

A student says y=3⁢x+1 is always above y=x+1. Test the claim.

Worked solution

  1. 1

    Try a positive input.

    3⁢(2)+1=72+1=3

    At x equal to 2, the first rule is higher, but one supporting case does not prove "always".

  2. 2

    Test a negative input.

    3⁢(−2)+1=−5−2+1=−1

    The negative input makes the larger x-coefficient produce a lower output.

  3. 3

    Reject the universal claim.

    −5<−1

    One counterexample is sufficient to disprove a statement about every input.

  4. 4

    Explain the full comparison.

    (3⁢x+1)−(x+1)=2⁢xx=0⇒y=1

    The first line is lower for negative x, higher for positive x, and equal at (0,1).

Answer

The claim is false; x=−2 gives a counterexample.

03 / YOUR TURN

Try it yourself.

Check your understanding

If y=−2⁢x+5 changes to y=−2⁢x+2, what happens to the graph?

Show answer & reasoning

It shifts down 3 units and remains parallel.

The output difference is (−2⁢x+2)−(−2⁢x+5)=−3 for every x. The line therefore moves down 3 units and remains parallel because its gradient stays −2.

Keep practising

6 worksheet questions · 16 marks

Read the questions online
  1. Complete the outputs for y=x+2 and y=x−1 at x=−1,0,1.
    3 marks
  2. Predict the change from y=4⁢x−2 to y=4⁢x+5 without plotting.
    2 marks
  3. Where do y=−x+3, y=2⁢x+3 and y=5⁢x+3 all meet? Explain.
    2 marks
  4. For y=m⁢x+2, which value m=1 or m=3 gives the larger output at x=−2? Show both values.
    3 marks
  5. Design two distinct lines that meet at (0,−1), then verify the common point.
    3 marks
  6. A graphing screen suggests y=0.5⁢x+2 and y=0.5⁢x+2.1 are the same line. Explain how to check.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Complete the outputs for y=x+2 and y=x−1 at x=−1,0,1.
    3 marks

    Substitute each input into both rules.

    The first output is always 3 greater.

    First rule: 1, 2, 3. Second rule: −2,−1,0.
  2. Predict the change from y=4⁢x−2 to y=4⁢x+5 without plotting.
    2 marks

    The gradients are equal.

    The intercept increases by 5−(−2)=7.

    A shift up 7 units; the lines are parallel.
  3. Where do y=−x+3, y=2⁢x+3 and y=5⁢x+3 all meet? Explain.
    2 marks

    For x=0, the m⁢x term is zero in each rule.

    All three rules then give y=3.

    (0,3)
  4. For y=m⁢x+2, which value m=1 or m=3 gives the larger output at x=−2? Show both values.
    3 marks

    For m=1, y=−2+2=0.

    For m=3, y=−6+2=−4.

    m=1 gives 0, which is larger than −4 for m=3.
  5. Design two distinct lines that meet at (0,−1), then verify the common point.
    3 marks

    Choose different gradients with the same intercept −1.

    Substituting x=0 gives y=−1 in both.

    For example, y=2⁢x−1 and y=−x−1.
  6. A graphing screen suggests y=0.5⁢x+2 and y=0.5⁢x+2.1 are the same line. Explain how to check.
    3 marks

    The same gradient means they are parallel.

    The different intercepts show they are not the same line.

    A large viewing window can hide a small separation.

    Compare exact equations or substitute x=0: the outputs are 2 and 2.1, so the lines are distinct and parallel.
Checking saved progress…
Curriculum reference & lesson scope

Australian Curriculum v9 and SA Curriculum Mathematics

Gradient, midpoint and distance; algebraic and graphical straight-line relationships; interpreting models and testing parameters. Parallel and perpendicular lines are included as a natural school-course extension. All explanations and questions are original.

Official curriculum source ↗

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