ASCENTLEARNING
Join a weekly class
Skip to learning content
YEAR 9 · PROBABILITY · 14 MIN

Systematic lists, arrays, tables and trees

Use lists, arrays, tables and trees to record every stage systematically.

In this lesson

Before you start
  • Complete outcomes and fractions
01 / LEARN

Understand the idea.

Choose a useful representation

Choose a representation that makes missing outcomes easy to spot. A systematic list fixes the first choice while varying the second. In a two-way table or array, each row-column pairing records one complete two-stage outcome.

A tree records stages in sequence and can show how later choices depend on earlier results. Follow branches all the way to a leaf to read a complete outcome; a point halfway through the tree is only a partial result.

Follow a path or combine leaves

In the displayed tree, H followed by 2 is one full path. Its probability is 12×13=16. Multiplication follows the stages of one path, using the probability written on each branch.

An even spinner result can occur through H2 or T2. These are different, non-overlapping outcomes, so add their probabilities: 16+16=13. Keep the first-stage result when identifying leaves, even if the event mentions only the spinner.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

A letter-number code

A code uses A or B followed by 1, 2, 3 or 4. List all codes.

Worked solution

  1. 1

    List all codes beginning with A.

    A1, A2, A3, A4

    Holding the first character fixed lets each allowed number appear exactly once.

  2. 2

    List all codes beginning with B.

    B1, B2, B3, B4

    B is the only other first character, and the same four numbers remain available.

  3. 3

    Check that the list is complete.

    2×4=8 codes

    The two groups contain four distinct codes each, covering every permitted letter-number pairing.

Answer

Eight codes: A1, A2, A3, A4, B1, B2, B3, B4.

EXAMPLE 02

Two-dice sum

Two fair independent dice are rolled. Find P(sum 5).

Worked solution

  1. 1

    Count all ordered dice outcomes.

    6×6=36

    Each first-die value has six possible second-die values; fairness and independence make these pairs equally likely.

  2. 2

    List the ordered pairs whose sum is 5.

    (1,4), (2,3),(3,2), (4,1)

    Trying first-die values in order gives exactly four valid second-die values.

  3. 3

    Calculate the probability from the two counts.

    P⁢(sum 5)=436=19

    The four listed pairs are distinct favourable outcomes among the 36 equally likely pairs.

Answer

4⁢/36=1⁢/9.

03 / YOUR TURN

Try it yourself.

Check your understanding

How many leaves for 3 first-stage options and 5 second-stage options, with all pairings allowed?

Show answer & reasoning

15

Each of the three first-stage choices has five continuations. With all pairings allowed, there are 3×5=15 leaves, each representing one complete outcome.

Keep practising

6 worksheet questions · 12 marks

Read the questions online
  1. List all ordered two-letter codes using X and Y, allowing repeats.
    1 mark
  2. A meal has 3 main choices and 2 drinks. How many complete meals can be formed?
    2 marks
  3. List the ordered outcomes with sum 4 when two dice are rolled.
    2 marks
  4. For two fair independent dice, find P⁢(sum 4).
    2 marks
  5. Use the displayed tree to find P⁢(H then 3).
    2 marks
  6. For a code A, B or C followed by 0 or 1, explain why A0, B1, C0 is incomplete.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. List all ordered two-letter codes using X and Y, allowing repeats.
    1 mark

    Hold the first letter fixed while changing the second.

    XX, XY, YX, YY.
  2. A meal has 3 main choices and 2 drinks. How many complete meals can be formed?
    2 marks

    A 3 by 2 array has six cells.

    6
  3. List the ordered outcomes with sum 4 when two dice are rolled.
    2 marks

    Try first-die results in order.

    (1,3), (2,2), (3,1).
  4. For two fair independent dice, find P⁢(sum 4).
    2 marks

    Three of 36 outcomes are favourable.

    112
  5. Use the displayed tree to find P⁢(H then 3).
    2 marks

    Multiply the branch probabilities: 12×13.

    16
  6. For a code A, B or C followed by 0 or 1, explain why A0, B1, C0 is incomplete.
    3 marks

    Each letter needs both digits.

    There should be six codes.

    A1, B0 and C1 are missing.
Checking saved progress…
Curriculum reference & lesson scope

Australian Curriculum v9 / SA Curriculum Mathematics

Year 9 compound-event sample spaces, probabilities, experiments and simulations.

Official curriculum source ↗

Save your next step.

Create a free account to save your learning progress. Lessons and downloads stay free, with or without an account.

Create free account