Understand the idea.
What per means
The word per means for each one. A rate of dollars per litre connects cost with volume: each litre corresponds to AUD . To find this rate from a purchase, divide dollars by litres, in that order.
The order of the units tells you what the answer means. Litres per minute measures filling speed; minutes per litre measures the time for one litre. Reversing the division gives a different rate, so always label the result.
Divide, then scale
Dividing both quantities by the same number turns the given comparison into a rate per one. Once that unit rate is known, multiply by the new number of units. This scaling assumes the rate remains unchanged.
Check a unit rate by multiplying it by the original number of units: the original total should return. Keep unrounded values during calculations and round a final money amount to cents when necessary.
See the method in action.
Cost per litre
Eight litres of paint cost AUD 24. Find the unit price and the cost of 5 L at the same rate.
Worked solution
- 1
Divide cost by volume.
A price per litre has dollars as its numerator and litres as its denominator.
- 2
Scale the unit price to five litres.
Each of the five litres costs the same AUD 3.
- 3
Check against the original purchase.
The unit price reproduces the given cost of eight litres.
AUD 3/L; AUD 15 for 5 L.
Words per minute
A speaker reads 375 words in 5 minutes. Find the average rate.
Worked solution
- 1
Form a words-per-minute rate.
The requested rate compares the number of words with the elapsed time.
- 2
Divide to find the rate per minute.
Dividing by five expresses the total over one minute instead of five.
- 3
Check the five-minute total.
The average rate accounts for the full reading, without claiming every minute was equally fast.
75 words/minute.
Try it yourself.
Check your understanding
A tap fills 28 L in 4 minutes. What is its rate?
Show answer & reasoning
7 L/min.
For litres per minute, divide volume by time: . Over four minutes this gives L, as required.
Keep practising
6 worksheet questions · 10 marks
Read the questions online
- Six kilograms cost AUD 18. Find the cost per kilogram.1 mark
- A car travels 240 km in 3 hours. Find its average speed.1 mark
- A pump moves 42 L in 7 minutes. Find its rate.1 mark
- Three litres of juice cost AUD 8.40. Find the unit price.2 marks
- A machine makes 150 items in 12 seconds. Find the average rate.2 marks
- A 0.6 kg bag costs AUD 5.40. Find the price per kilogram and per 100 g.3 marks
Read the worked solutions
Equivalent correct methods earn the corresponding marks. Include units where asked.
- Six kilograms cost AUD 18. Find the cost per kilogram.1 mark
.
AUD 3/kg. - A car travels 240 km in 3 hours. Find its average speed.1 mark
.
80 km/h. - A pump moves 42 L in 7 minutes. Find its rate.1 mark
.
6 L/min. - Three litres of juice cost AUD 8.40. Find the unit price.2 marks
.
AUD 2.80/L. - A machine makes 150 items in 12 seconds. Find the average rate.2 marks
.
Check: .
12.5 items/s. - A 0.6 kg bag costs AUD 5.40. Find the price per kilogram and per 100 g.3 marks
.
100 g is one tenth of a kilogram, so divide 9 by 10.
AUD 9/kg; AUD 0.90 per 100 g.
Curriculum reference & lesson scope
Australian Curriculum v9 / SA Curriculum Mathematics
Ratio scaling and division review; unit rates; comparing rates and best buys; speed, distance and time; converting compatible units; direct-proportion tables and graphs; modelling practical rate problems and checking assumptions.
Official curriculum source ↗