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YEAR 8 · INDEX LAWS · 16 MIN

Powers of powers

Treat a power raised to another power as repeated groups of equal factors.

In this lesson

Before you start
  • Exponent notation
  • Multiplying same-base powers
01 / LEARN

Understand the idea.

Groups of groups

A power of a power repeats the entire inner power. In (23)4, there are four groups, each containing three factors of two. Counting all the factors gives 3×4=12, so the result is 212.

The multiplication of exponents follows from grouping factors, rather than from a new rule for the base. With positive whole-number exponents, (am)n contains n groups of m factors, giving am⁢n.

(am)n=am⁢n

Choose by structure

Read the structure before choosing an index law. In 23×24, add the exponents because two products are joined. In (23)4, multiply them because the whole inner product is repeated four times.

Keep brackets around a negative base. An even number of negative factors gives a positive result; an odd number gives a negative result. The brackets in (−3)6 tell you that the negative sign is part of every factor.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Four groups of three

Write (23)4 as one power and evaluate.

Worked solution

  1. 1

    Expand the outer repetition.

    (23)4=23×23×23×23

    The outer exponent four means four copies of the complete inner power.

  2. 2

    Count the factors of two.

    (23)4=23×4=212

    Four groups of three factors contain twelve factors altogether.

  3. 3

    Evaluate the resulting power.

    212=4096

    The expression is twelve copies of two multiplied together.

Answer

212=4096

EXAMPLE 02

An even final exponent

Evaluate ((−3)2)3.

Worked solution

  1. 1

    Combine the nested powers.

    ((−3)2)3=(−3)2×3

    The outer power repeats a pair of negative-three factors three times.

  2. 2

    Simplify the exponent.

    (−3)2×3=(−3)6

    Three pairs contain six factors of negative three.

  3. 3

    Determine the sign and value.

    (−3)6=36=729

    Six is even, so the negative factors pair to produce a positive result.

Answer

729

03 / YOUR TURN

Try it yourself.

Check your understanding

Write (73)2 as one power.

Show answer & reasoning

76

Two groups each contain three factors of seven. Therefore (73)2=73×2=76.

Keep practising

6 worksheet questions · 13 marks

Read the questions online
  1. Write (52)3 as one power.
    2 marks
  2. Write (34)2 as one power.
    2 marks
  3. Write (103)2 as one power.
    2 marks
  4. Evaluate (22)3.
    2 marks
  5. Evaluate ((−2)3)2.
    2 marks
  6. Find n if (42)n=48.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Write (52)3 as one power.
    2 marks

    2×3=6.

    56
  2. Write (34)2 as one power.
    2 marks

    4×2=8.

    38
  3. Write (103)2 as one power.
    2 marks

    3×2=6.

    106
  4. Evaluate (22)3.
    2 marks

    22×3=26=64.

    64
  5. Evaluate ((−2)3)2.
    2 marks

    (−2)3×2=(−2)6=64.

    64
  6. Find n if (42)n=48.
    3 marks

    2⁢n=8, so n=4.

    4
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Curriculum reference & lesson scope

Australian Curriculum v9 / SA Curriculum Mathematics

Exponent notation review; multiplying same-base powers; dividing same-base powers; powers of powers; zero index; combining numerical index laws. Negative indices and general variable index laws become Year 9 core.

Official curriculum source ↗

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