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YEAR 8 · PROBABILITY · 15 MIN

Two-stage sample spaces

List ordered two-stage outcomes without missing or repeating possibilities.

In this lesson

Before you start
  • Read tables and calculate simple fractions or percentages.
01 / LEARN

Understand the idea.

Keep the stages in order

A two-stage outcome records what happens first and second, keeping their order. A head followed by spinner 2 can be written H2. List every second-stage possibility beneath each first-stage possibility so that no complete result is omitted.

A table uses first-stage results for rows and second-stage results for columns; each cell is a complete ordered outcome. A tree shows the same construction through branches. Either method lets you check the systematic list rather than relying on guesses.

Count elementary outcomes

If every first-stage outcome allows the same number of second-stage possibilities, multiply the counts. Two six-sided dice produce 6×6=36 ordered pairs. To turn a count into a probability by division, also justify that the elementary outcomes are equally likely.

Do not replace elementary outcomes by summaries too early. Two dice can show 7 in six different ordered ways but 2 in only one. Similarly, two differently labelled blue tokens remain distinct possible draws even when their colours match.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Worked example 1

List outcomes for a fair coin then an independent fair spinner labelled 1,2,3.

Worked solution

  1. 1

    List outcomes beginning with a head.

    H1, H2, H3

    After H, each of the spinner's three labels is possible.

  2. 2

    List outcomes beginning with a tail.

    T1, T2, T3

    The same three spinner labels are possible after T.

  3. 3

    Check the complete count and likelihoods.

    2×3=6,12×13=16

    The fair coin and independent fair spinner make all six listed ordered outcomes equally likely.

Answer

H1,H2,H3,T1,T2,T3.

EXAMPLE 02

Worked example 2

Is “one head” a single elementary outcome for two ordered fair coins?

Worked solution

  1. 1

    List the ordered coin results.

    H⁢H, H⁢T, T⁢H, T⁢T

    First-coin and second-coin results distinguish HT from TH.

  2. 2

    Select outcomes containing exactly one head.

    {H⁢T,T⁢H}

    A head can occur on either the first or the second coin, so this event contains two elementary outcomes.

  3. 3

    Calculate the event probability.

    P⁢(one head)=24=12

    Two favourable results occur among four equally likely ordered outcomes of fair coin tosses.

Answer

No; P(one head)=1/2.

03 / YOUR TURN

Try it yourself.

Check your understanding

How many ordered outcomes come from two independent four-sector spinners?

Show answer & reasoning

16.

For each of four first-spinner results, there are four second-spinner results. Hence 4×4=16 ordered outcomes; counting them does not require assuming that their probabilities are equal.

Keep practising

6 worksheet questions · 13 marks

Read the questions online
  1. List the sample space for two ordered coin tosses.
    2 marks
  2. A coin then an A,B,C spinner has how many ordered outcomes?
    1 mark
  3. List outcomes for two ordered spinners each labelled 1,2.
    2 marks
  4. For a coin then a 1,2,3 spinner, list outcomes with a tail or spinner 3.
    3 marks
  5. How many ordered pairs can two standard dice produce? Why do (2,5) and (5,2) differ?
    2 marks
  6. A bag holds R1,R2,B. Draw two without replacement. List the ordered physical pairs.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. List the sample space for two ordered coin tosses.
    2 marks

    Pair each first result with both second results.

    HH,HT,TH,TT.
  2. A coin then an A,B,C spinner has how many ordered outcomes?
    1 mark

    2×3=6.

    6.
  3. List outcomes for two ordered spinners each labelled 1,2.
    2 marks

    Both stages are recorded.

    (1,1),(1,2),(2,1),(2,2).
  4. For a coin then a 1,2,3 spinner, list outcomes with a tail or spinner 3.
    3 marks

    Include the overlapping T3 only once.

    T1,T2,T3,H3.
  5. How many ordered pairs can two standard dice produce? Why do (2,5) and (5,2) differ?
    2 marks

    6×6=36, and die order is retained.

    36; the first-die result differs.
  6. A bag holds R1,R2,B. Draw two without replacement. List the ordered physical pairs.
    3 marks

    There are 3 first choices and 2 remaining choices, giving 6 pairs.

    (R1,R2),(R1,B),(R2,R1),(R2,B),(B,R1),(B,R2).
Checking saved progress…
Curriculum reference & lesson scope

Australian Curriculum v9 and SA Curriculum

Complementary events; two-stage sample spaces; tables, trees and Venn diagrams; probabilities of combined outcomes; experimental versus theoretical results; compound-event simulations and describing results. Formal conditional probability is Year 10.

Official curriculum source ↗

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