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YEAR 10 · EXPONENTIAL RELATIONSHIPS · 15 MIN

Logarithms as inverses

Understand a logarithm as the exponent needed to produce a positive number.

In this lesson

Before you start
  • Exponential notation
  • Inverse operations
01 / LEARN

Understand the idea.

A logarithm answers an exponent question

A logarithm asks for an exponent: logba=c means exactly bc=a. The base must satisfy b>0 and b≠1, and the real logarithm input must satisfy a>0.

Read log28 as the power on 2 that produces 8. A logarithm can return zero, positive or negative values: for example, log21=0 and log2(12)=−1.

Undoing exponential functions

Exponentials and logarithms of the same base are inverses: logb(bx)=x for real x, and blogba=a for a>0. Keep the base unchanged when moving between the two forms.

On a scientific calculator, the key labelled log usually means base 10, while ln means base e. State the intended base rather than assuming different logarithms give the same output.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Convert notation

Evaluate log381.

Worked solution

  1. 1

    Translate the logarithm into an exponent question.

    log381=c⟺3c=81

    The logarithm is the exponent on the stated base.

  2. 2

    Express the input as a power of three.

    81=34

    Four factors of 3 multiply to 81.

  3. 3

    Read the required exponent.

    log381=4

    The unique exponent producing 81 is 4.

Answer

4

EXAMPLE 02

A negative logarithm

Evaluate log10(0.001).

Worked solution

  1. 1

    Express the decimal as a power of ten.

    0.001=11000=10−3

    Three places below the units place corresponds to the exponent −3.

  2. 2

    Apply the inverse relationship.

    log10(10−3)=−3

    A base-10 logarithm recovers the exponent of a power of 10.

  3. 3

    Check the sign using the input.

    10−3=0.001>0

    The negative answer is allowed; it is the logarithm input, rather than its output, that must be positive.

Answer

−3

03 / YOUR TURN

Try it yourself.

Check your understanding

Write log5125=3 in exponential form.

Show answer & reasoning

53=125

The statement says the exponent on base 5 is 3. Therefore its exponential form is 53=125.

Keep practising

6 worksheet questions · 14 marks

Read the questions online
  1. Evaluate log216.
    2 marks
  2. Evaluate log71.
    2 marks
  3. Evaluate log10100000.
    2 marks
  4. Write 4−2=116 in logarithmic form.
    2 marks
  5. Give the real domain of log3(x−4).
    3 marks
  6. Explain why log20 is undefined as a real number.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Evaluate log216.
    2 marks

    24=16.

    4
  2. Evaluate log71.
    2 marks

    70=1.

    0
  3. Evaluate log10100000.
    2 marks

    105=100000.

    5
  4. Write 4−2=116 in logarithmic form.
    2 marks

    The log output is the exponent −2.

    log4(116)=−2
  5. Give the real domain of log3(x−4).
    3 marks

    The input must be positive: x−4>0.

    x>4
  6. Explain why log20 is undefined as a real number.
    3 marks

    2x approaches but never reaches zero, so no real exponent gives the required input.

    No real power of 2 is zero.
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Curriculum reference & lesson scope

Australian Curriculum v9 and SA Curriculum Mathematics

Integer and fractional index laws; connecting fractional powers with roots; simplifying surds; operations with surds; rationalising denominators; exact and approximate values; exponential tables and graphs; growth/decay factors; comparing linear/quadratic/exponential patterns; exponential equations; logarithms as inverses; logarithm laws; interpreting logarithmic scales; graph transformations and parameter experiments; choosing and evaluating models.

Official curriculum source ↗

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