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YEAR 10 · ALGEBRA · 15 MIN

Common-factor factorisation

Reverse the distributive law by identifying the greatest factor shared by every term.

In this lesson

Before you start
  • Factors and multiples
  • Expanding brackets
01 / LEARN

Understand the idea.

Factorising reverses expansion

Factorising writes a sum as a product, reversing the distributive law. Find the greatest numerical factor of all coefficients, then include only variables shared by every term. For a shared variable, take its lowest power in those terms.

Check every term

The bracket entries tell you what must multiply the outside factor to recover each original term. Obtain them by dividing each term by that factor, keeping signs attached. If an entire term is extracted, its bracket entry is 1, not zero.

A negative outside factor can make the first bracket term positive. Expand the completed product as a check: recovering every original term confirms the factorisation, including any constant or negative term.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

The greatest shared factor

Factorise 12x2y+18⁢xy2.

Worked solution

  1. 1

    Find the greatest shared factor.

    12x2y=6⁢x⁢y⁢(2⁢x)18⁢xy2=6⁢x⁢y⁢(3⁢y)

    The coefficients share 6, and both terms contain at least one x and one y.

  2. 2

    Place the remaining factors in a bracket.

    12x2y+18⁢xy2=6⁢x⁢y⁢(2⁢x+3⁢y)

    The distributive law combines terms with the same outside factor.

  3. 3

    Check by expanding.

    6⁢x⁢y⁢(2⁢x+3⁢y)=12x2y+18⁢xy2

    Both original terms and their powers are recovered.

Answer

6⁢x⁢y⁢(2⁢x+3⁢y)

EXAMPLE 02

An outside negative

Factorise −8⁢p+12.

Worked solution

  1. 1

    Choose a negative common factor.

    −8⁢p+12=(−4)⁢(2⁢p)+(−4)⁢(−3)

    Both coefficients are divisible by −4; the positive constant needs a negative bracket entry.

  2. 2

    Extract that factor.

    −8⁢p+12=−4⁢(2⁢p−3)

    The bracket records the two factors left after extracting −4.

  3. 3

    Expand to check both signs.

    −4⁢(2⁢p−3)=−8⁢p+12

    The product of the two negatives reproduces the positive constant.

Answer

−4⁢(2⁢p−3)

03 / YOUR TURN

Try it yourself.

Check your understanding

Factorise 15a2−10⁢a.

Show answer & reasoning

5⁢a⁢(3⁢a−2)

The greatest shared factor is 5⁢a. The remaining factors are 3⁢a and −2, so 15a2−10⁢a=5⁢a⁢(3⁢a−2). Expansion verifies the signs and powers.

Keep practising

6 worksheet questions · 14 marks

Read the questions online
  1. Factorise 8⁢x+24.
    2 marks
  2. Factorise 14a2+21⁢a.
    2 marks
  3. Factorise 18⁢x⁢y−12⁢x.
    2 marks
  4. Factorise −10m2+15⁢m.
    2 marks
  5. A garden contains 4⁢x rows with 3⁢y+2 plants in each row. Its expanded plant count is 12⁢x⁢y+8⁢x. Factorise this count and identify the common factor.
    3 marks
  6. Sam writes x3+x2=x2(x). Correct the answer and explain the missing term.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Factorise 8⁢x+24.
    2 marks

    The greatest common factor is 8.

    8⁢(x+3)
  2. Factorise 14a2+21⁢a.
    2 marks

    Extract 7⁢a.

    7⁢a⁢(2⁢a+3)
  3. Factorise 18⁢x⁢y−12⁢x.
    2 marks

    Extract 6⁢x.

    6⁢x⁢(3⁢y−2)
  4. Factorise −10m2+15⁢m.
    2 marks

    Extract −5⁢m; 5⁢m⁢(−2⁢m+3) is equivalent.

    −5⁢m⁢(2⁢m−3)
  5. A garden contains 4⁢x rows with 3⁢y+2 plants in each row. Its expanded plant count is 12⁢x⁢y+8⁢x. Factorise this count and identify the common factor.
    3 marks

    Divide both terms by 4⁢x.

    4⁢x⁢(3⁢y+2); common factor 4⁢x.
  6. Sam writes x3+x2=x2(x). Correct the answer and explain the missing term.
    3 marks

    Dividing x3 by x2 gives x.

    Dividing x2 by x2 gives 1, which cannot be omitted.

    x2(x+1)
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Curriculum reference & lesson scope

Australian Curriculum v9 and South Australian Mathematics Curriculum

Year 10 algebra, including the approved fuller school-course treatment of rational expressions and formula restrictions; quadratic methods are in their own chapter.

Official curriculum source ↗

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