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YEAR 11 · EXPONENTIALS AND LOGARITHMS · 18 MIN

Meaning of a logarithm

Read a logarithm as an exponent and move confidently between exponential and logarithmic statements.

In this lesson

Before you start
  • Exponential equations and positive bases
01 / LEARN

Understand the idea.

A logarithm answers an exponent question

A logarithm answers an exponent question: logba asks which power of b produces a. Rewriting in exponential form often makes an exact value immediate. The logarithm is a number, rather than a multiplication instruction.

For real logarithms, require b>0, b≠1 and a>0. A positive base different from 1 gives a one-to-one exponential function, so each permitted argument corresponds to exactly one exponent.

logba=cbc=a

Base ten and inverse relationships

Here an unsubscripted logarithm means base ten, matching the usual calculator log key. Powers of ten provide reference values: log100=2 and log0.01=−2. A positive argument between zero and one has a negative base-ten logarithm.

A logarithm and exponentiation undo one another when their bases match. Thus blogbx=x for x>0, while logb(bu)=u for every real u. Check the base and domain before using either identity.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Read an exact logarithm

Find log381.

Worked solution

  1. 1

    Name the required exponent.

    log381=c⟺3c=81

    The logarithm records the exponent on base 3.

  2. 2

    Express the argument as a power of 3.

    81=34

    Four factors of 3 multiply to give 81.

  3. 3

    Match the exponents.

    c=4⟹log381=4

    The exponential with base 3 is one-to-one.

Answer

4

EXAMPLE 02

A logarithm of a small quantity

Solve 10x=0.004.

Worked solution

  1. 1

    Use the matching base-ten inverse.

    10x=0.004⟹x=log(0.004)

    The argument is positive, so its real common logarithm exists.

  2. 2

    Locate the exponent before calculating.

    10−3=0.001<0.004<0.01=10−2⟹−3<x<−2

    A base-ten exponential increases with its exponent.

  3. 3

    Evaluate and check the sign.

    x=log(0.004)≈−2.39794

    The result lies between the reference exponents, consistent with an argument below 1.

Answer

x≈−2.39794

03 / YOUR TURN

Try it yourself.

Check your understanding

Write log5125=3 in exponential form.

Show answer & reasoning

53=125

The base is 5 and the recorded exponent is 3. Exponential form is 53=125; indeed, multiplying three factors of 5 gives 125.

Keep practising

6 worksheet questions · 14 marks

Read the questions online
  1. Evaluate log232.
    2 marks
  2. Evaluate log0.001.
    2 marks
  3. Write 72=49 as a logarithmic statement.
    2 marks
  4. Evaluate 10log7.
    2 marks
  5. Explain why log0 is not a real number.
    3 marks
  6. If logN=4.2, between which consecutive powers of ten does N lie?
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Evaluate log232.
    2 marks

    25=32.

    5
  2. Evaluate log0.001.
    2 marks

    10−3=0.001.

    -3
  3. Write 72=49 as a logarithmic statement.
    2 marks

    The exponent 2 becomes the value of the logarithm.

    log749=2
  4. Evaluate 10log7.
    2 marks

    The exponential and its base-ten logarithm are inverse operations for positive inputs.

    7
  5. Explain why log0 is not a real number.
    3 marks

    10x>0 for every real x; it approaches zero without reaching it.

    No real exponent on 10 gives zero.
  6. If logN=4.2, between which consecutive powers of ten does N lie?
    3 marks

    4<4.2<5 and the function 10x increases.

    104<N<105
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics: exponential and logarithmic functions, growth models and numerical/algebraic prerequisites.

Official curriculum source ↗

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