Understand the idea.
Match triangles before matching lengths
Congruent triangles have matching lengths and angles; similar triangles have matching angles and proportional lengths. Use a valid test before taking corresponding parts: SSS, SAS, ASA/AAS or RHS for congruence, and AA or proportional-side tests for similarity.
Write triangle names in corresponding order. From , match A to D, B to E and C to F. Keep every ratio in the same direction; three equal angles establish shape but do not fix size.
Turn the triangle fact into the target result
Build a geometric proof in four stages: name the triangles, justify enough equal sides or angles, state a congruence or similarity test, then extract the target fact. Equal radii, shared sides, vertical angles and angles on one chord often provide the links.
For a proportional equation, check which endpoints correspond before selecting lengths. Do not assume a right angle or midpoint from appearance. State the given facts and derived relations so that the argument applies to every non-degenerate configuration meeting the hypotheses.
See the method in action.
A median in an isosceles triangle
In triangle ABC, AB and D is the midpoint of BC. Prove AD is perpendicular to BC.
Worked solution
- 1
List the three matched side equalities.
The first equality is given, the second follows from D being the midpoint, and AD is shared.
- 2
Establish congruence and equal angles.
SSS proves the triangles congruent, so corresponding angles are equal.
- 3
Use the straight line through B, D and C.
Equal adjacent angles on a straight line must both be right angles.
- 4
State the perpendicularity.
AD meets BC at a right angle at D.
AD is perpendicular to BC.
An altitude in a right triangle
A right triangle ABC has right angle A. The altitude AH meets hypotenuse BC at H. Prove .
Worked solution
- 1
Identify the right-angle pair.
AH is an altitude to BC, and B, H and C are collinear.
- 2
Match another angle pair.
Both angles are complementary to angle C: one in triangle ABC and the other in triangle CAH.
- 3
Establish similarity in matching order.
AA gives the correspondence A to C, B to A and H to H.
- 4
Compare corresponding sides and multiply.
The positive altitude permits cross-multiplication; CH and HC denote the same segment.
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Try it yourself.
Check your understanding
Similar triangles have matching side lengths 4 and 6. What is their large-to-small area ratio?
Show answer & reasoning
.
The large-to-small length ratio is . Areas scale as the square of the length factor, so the area ratio is .
Keep practising
6 worksheet questions · 16 marks
Read the questions online
- Triangles and have , and . State a valid conclusion with a test.2 marks
- A student proves all three corresponding angles equal and claims congruence. Give a concrete counterexample.2 marks
- Triangles and are similar in that order. , and . Find .2 marks
- and are tangents from to a circle with centre . Prove bisects angle .4 marks
- An altitude to the hypotenuse divides it into lengths 4 and 9. Find the altitude and explain the theorem used.3 marks
- In the same altitude construction, the hypotenuse pieces are and . Explain why is not the altitude in general.3 marks
Read the worked solutions
Equivalent correct methods earn the corresponding marks. Include units where asked.
- Triangles and have , and . State a valid conclusion with a test.2 marks
All three corresponding sides are equal.
by SSS. - A student proves all three corresponding angles equal and claims congruence. Give a concrete counterexample.2 marks
All corresponding angles are , but their side lengths differ.
Equilateral triangles with side lengths 2 and 5. - Triangles and are similar in that order. , and . Find .2 marks
Scale from to is ; .
15 units. - and are tangents from to a circle with centre . Prove bisects angle .4 marks
as radii; is a shared hypotenuse; tangent-radius angles and are right.
Corresponding angles and are equal.
Triangles and are congruent by RHS. - An altitude to the hypotenuse divides it into lengths 4 and 9. Find the altitude and explain the theorem used.3 marks
By similarity, . Take .
6 units. - In the same altitude construction, the hypotenuse pieces are and . Explain why is not the altitude in general.3 marks
The geometric-mean theorem gives .
For example, , give hypotenuse 13 and altitude 6, not 13.
It is the full hypotenuse, whereas the altitude is .
Curriculum reference & lesson scope
SACE Board of South Australia
Stage 1 Mathematics: geometric reasoning and real-number/proof material, regrouped into a school chapter; all exercises are original.
Official curriculum source ↗