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YEAR 11 · MATRICES AND TRANSFORMATIONS · 20 MIN

Singular matrices

Interpret a zero determinant as lost information and distinguish no-solution and many-solution systems.

In this lesson

Before you start
  • Determinants and inverses
01 / LEARN

Understand the idea.

What singular means

A square matrix is singular when its determinant is zero. For a non-zero singular 2×2 matrix, its dependent columns force every output onto one line through the origin. The zero matrix instead sends every input to the origin.

Collapse loses information: distinct inputs can have the same output. An inverse could not know which input to return, so no singular square matrix has an inverse that recovers every original vector.

A singular system is not automatically inconsistent

Test whether b is an attainable output. A nonzero singular 2×2 matrix has a line image; the zero matrix has image {0}. A consistent singular system has infinitely many solutions; otherwise it has none.

Test consistency using the original equations. If one left side is twice another, its right side must also double. A zero determinant rules out a unique solution, but alone does not distinguish inconsistency from infinitely many solutions.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

A collapsed plane

For A=(1224), find the image of (x,y).

Worked solution

  1. 1

    Multiply by the general input vector.

    A(xy)=(x+2⁢y2⁢x+4⁢y)

    A general input describes the entire image, rather than just selected test points.

  2. 2

    Factor the dependence between output coordinates.

    s=x+2⁢y,A(xy)=(s2⁢s)

    The second output coordinate is twice the first for every input.

  3. 3

    Identify the output line.

    X=s,Y=2⁢s⟹Y=2⁢X

    Capital letters distinguish output coordinates from the original input coordinates.

  4. 4

    Check that the whole line is reached.

    A(s0)=(s2⁢s)(s∈ℝ)

    Choosing this input produces every real value of the line parameter.

Answer

A⁢(x,y)T=(x+2⁢y,2⁢x+4⁢y)T, on Y=2⁢X.

EXAMPLE 02

Two right-hand sides

Compare x+2⁢y=3, 2⁢x+4⁢y=6 with x+2⁢y=3, 2⁢x+4⁢y=7.

Worked solution

  1. 1

    Double the first equation.

    2⁢(x+2⁢y)=2⁢(3)⟹2⁢x+4⁢y=6

    Any solution of the first equation must satisfy its doubled version.

  2. 2

    Parametrise the first system.

    y=t,x=3−2⁢t,t∈ℝ

    The second equation repeats the first, leaving one free real parameter.

  3. 3

    Verify the family.

    2⁢(3−2⁢t)+4⁢t=6

    Every parameter value satisfies the second equation as well as the first.

  4. 4

    Compare the second system.

    2⁢x+4⁢y=6and2⁢x+4⁢y=7

    The same left side cannot equal two different constants, so this system has no solution.

Answer

First: infinitely many solutions (3−2⁢t,t). Second: no solution.

03 / YOUR TURN

Try it yourself.

Check your understanding

Can a singular square matrix have a two-sided inverse?

Show answer & reasoning

No.

No. A singular square matrix sends some distinct inputs to the same output, so a two-sided inverse cannot recover both. Equivalently, its zero determinant cannot multiply with another determinant to give detI=1.

Keep practising

6 worksheet questions · 12 marks

Read the questions online
  1. Is (2613) singular?
    2 marks
  2. Find k so that (2k46) is singular.
    2 marks
  3. Solve x+y=4, 2⁢x+2⁢y=8 using a parameter.
    2 marks
  4. Explain why x+y=4, 2⁢x+2⁢y=9 is inconsistent.
    2 marks
  5. Find a non-zero vector sent to zero by (1−22−4).
    2 marks
  6. The matrix (3000) acts on the plane. Describe all its possible outputs.
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Is (2613) singular?
    2 marks

    The determinant is 6−6=0.

    Yes.
  2. Find k so that (2k46) is singular.
    2 marks

    Set 12−4⁢k=0.

    k=3.
  3. Solve x+y=4, 2⁢x+2⁢y=8 using a parameter.
    2 marks

    The second equation repeats the first.

    Choose y=t and obtain x=4−t.

    (x,y)=(4−t,t) for any real t.
  4. Explain why x+y=4, 2⁢x+2⁢y=9 is inconsistent.
    2 marks

    No pair can satisfy both statements.

    Doubling the first equation gives 8, not 9.
  5. Find a non-zero vector sent to zero by (1−22−4).
    2 marks

    2−2⁢(1)=0 and 2⁢(2)−4⁢(1)=0.

    For example (2,1).
  6. The matrix (3000) acts on the plane. Describe all its possible outputs.
    2 marks

    The output is (3⁢x,0).

    Every real x-coordinate is possible, but the y-coordinate is always zero.

    All points on the x-axis.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics: matrices and transformations; original lessons follow the approved school-sized chapter structure.

Official curriculum source ↗

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