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YEAR 7 · LINEAR EQUATIONS · 15 MIN

Writing an equation from a problem

Define an unknown, turn a short situation into an equation, solve it and explain what the answer means.

In this lesson

Before you start
  • Writing algebraic expressions
  • Solving one- and two-step equations
01 / LEARN

Understand the idea.

Say what the variable represents

Define the unknown before writing a model: let n be the number of tickets. At 4 dollars per ticket, the ticket cost is 4⁢n dollars. A 5 dollar booking fee paid once makes the total 4⁢n+5.

An equation sets this expression equal to a known total. A bill of 29 dollars gives 4⁢n+5=29. Keep each quantity consistent: the fee is added once, while the per-ticket price is multiplied by the ticket count.

Solve, check and interpret

Solve the model and then translate the variable back into the situation. From 4⁢n+5=29, remove the fee to get 4⁢n=24 and divide by the price per ticket to find n=6 tickets.

Check both the arithmetic and the meaning. Six tickets cost 24 dollars, and the fee brings the bill to 29 dollars. Counts of whole objects must be whole numbers, and a physical length must be positive in these problems.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

A starting cost and equal extras

A swimming session costs 3 dollars for entry plus 2 dollars for each equipment item hired. The total is 17 dollars. How many items were hired?

Worked solution

  1. 1

    Define the unknown and model the bill.

    2⁢h+3=17

    Let h be the number of hired items; each costs 2 dollars and entry adds 3 dollars once.

  2. 2

    Remove the entry charge from both sides.

    2⁢h+3−3=17−32⁢h=14

    The remaining 14 dollars pays only for equipment hire.

  3. 3

    Divide by the charge per item.

    2⁢h2=142h=7

    Each item contributes 2 dollars, so 14 dollars pays for 7 items.

  4. 4

    Check the complete bill.

    2×7+3=17

    Seven items plus the single entry charge reproduce the total.

Answer

7 equipment items

EXAMPLE 02

Use a perimeter equation

A rectangle is 5 cm long and w cm wide. Its perimeter is 26 cm. Find its width.

Worked solution

  1. 1

    Add all four sides to model the perimeter.

    w+5+w+5=262⁢w+10=26

    A rectangle has two sides of each length; every quantity here is measured in centimetres.

  2. 2

    Subtract the two known lengths.

    2⁢w+10−10=26−102⁢w=16

    The two widths account for the remaining 16 cm of perimeter.

  3. 3

    Divide the remaining total equally.

    w=162=8

    The two widths are equal, so each is 8 cm.

  4. 4

    Check all four sides.

    5+8+5+8=26

    The calculated width gives the stated 26 cm perimeter.

Answer

8 cm

03 / YOUR TURN

Try it yourself.

Check your understanding

A club charges 4 dollars for entry and 3 dollars per ride. A visitor pays 25 dollars. Write an equation and find the number of rides.

Show answer & reasoning

3⁢r+4=25; 7 rides.

Let r count rides. The total is 3⁢r+4=25. Removing the entry fee gives 3⁢r=21, so r=7 rides. The check 3×7+4=25 matches the bill.

Keep practising

6 worksheet questions · 18 marks

Read the questions online
  1. Mia has s stickers. She receives 9 more and now has 28. Write an equation and find her starting number.
    3 marks
  2. A rope was l metres long. Cutting off 7 m leaves 15 m. Write an equation and find its original length.
    3 marks
  3. Five equal boxes hold 45 books. Let b be the number of books in one box. Write and solve an equation.
    3 marks
  4. Some counters are shared equally among 4 pupils. Each pupil receives 8 counters. Use c for the total number. Write and solve an equation.
    3 marks
  5. A game costs 5 dollars for entry plus 2 dollars per round. A player pays 19 dollars. Write an equation and find the number of rounds.
    3 marks
  6. A rectangle is 6 cm long and w cm wide. Its perimeter is 30 cm. Form an equation and find the width.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Mia has s stickers. She receives 9 more and now has 28. Write an equation and find her starting number.
    3 marks

    Let s be the starting number.

    Subtract 9 from s+9=28: s=19.

    Check: 19+9=28.

    s+9=28; 19 stickers.
  2. A rope was l metres long. Cutting off 7 m leaves 15 m. Write an equation and find its original length.
    3 marks

    Let l be the original length in metres.

    Add 7 to both sides: l=22.

    Check: 22−7=15.

    l−7=15; 22 m.
  3. Five equal boxes hold 45 books. Let b be the number of books in one box. Write and solve an equation.
    3 marks

    Five equal groups give 5⁢b=45.

    Divide by 5: b=9.

    Check: 5×9=45.

    5⁢b=45; 9 books per box.
  4. Some counters are shared equally among 4 pupils. Each pupil receives 8 counters. Use c for the total number. Write and solve an equation.
    3 marks

    The total divided into 4 groups gives c÷4=8.

    Multiply by 4: c=32.

    Check: 32÷4=8.

    c÷4=8; 32 counters.
  5. A game costs 5 dollars for entry plus 2 dollars per round. A player pays 19 dollars. Write an equation and find the number of rounds.
    3 marks

    Let r be the number of rounds.

    Subtract 5: 2⁢r=14. Divide by 2: r=7.

    Check: 2×7+5=19.

    2⁢r+5=19; 7 rounds.
  6. A rectangle is 6 cm long and w cm wide. Its perimeter is 30 cm. Form an equation and find the width.
    3 marks

    The two lengths total 12 cm, so 2⁢w+12=30.

    Subtract 12: 2⁢w=18. Divide by 2: w=9.

    Check: 6+9+6+9=30 cm.

    2⁢w+12=30; 9 cm.
Checking saved progress…
Curriculum reference & lesson scope

Australian Curriculum v9 / SA Curriculum

Year 7 linear equations with natural-number solutions: equality, inverse operations, substitution checks and familiar models. Formal variables-on-both-sides techniques are not required here.

Official curriculum source ↗

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