ASCENTLEARNING
Join a weekly class
Skip to learning content
YEAR 12 · INTEGRATION · 16 MIN

Antiderivatives and constants

Reverse differentiation, keep the arbitrary constant, and check an antiderivative by differentiating it.

In this lesson

Before you start
  • Differentiating powers and polynomials
01 / LEARN

Understand the idea.

A family, not a single answer

An antiderivative reverses a derivative: if F′(x)=f⁡(x), then F is an antiderivative of f⁡. Adding a constant changes the height of the graph but leaves every gradient unchanged.

The symbol ∫f⁡(x)d⁢x asks for the whole family F⁢(x)+C on the interval considered. For example, x2+3 and x2−7 both differentiate to 2⁢x; the derivative cannot recover their different constants.

∫2⁢xd⁢x=x2+C

Reverse each term and check

To reverse a power derivative, increase the exponent by one and divide by that new exponent. The rule requires n≠−1. Integrate sums term by term, retaining the coefficient and sign of each term.

Check the result by differentiating it. Recovering every term of the integrand verifies the calculation; it does not determine C. A constant integrand needs an x because differentiating a multiple of x returns that constant.

∫xnd⁢x=xn+1n+1+C(n≠−1)
02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Worked example

Find ∫(6x2−4)d⁢x.

Worked solution

  1. 1

    Integrate the quadratic term.

    ∫6x2d⁢x=2x3+C1

    Increasing the power to 3 introduces a factor of 3 on differentiation, so divide the coefficient 6 by 3.

  2. 2

    Integrate the constant term.

    ∫(−4)d⁢x=−4⁢x+C2

    A constant rate accumulates in direct proportion to the input.

  3. 3

    Combine the terms and include the family.

    ∫(6x2−4)d⁢x=2x3−4⁢x+C

    Linearity allows separate integration, and one arbitrary constant represents the combined family.

  4. 4

    Differentiate to verify.

    dd⁢x⁢(2x3−4⁢x+C)=6x2−4

    The derivative recovers the complete integrand.

Answer

2x3−4⁢x+C

EXAMPLE 02

Worked example

Are F⁢(x)=x2+5 and G⁢(x)=x2−2 both antiderivatives of 2⁢x?

Worked solution

  1. 1

    Differentiate the first function.

    F′(x)=dd⁢x⁢(x2+5)=2⁢x

    The derivative of the added constant is zero.

  2. 2

    Differentiate the second function.

    G′(x)=dd⁢x⁢(x2−2)=2⁢x

    The different constant also disappears on differentiation.

  3. 3

    Identify their relationship.

    F⁢(x)−G⁢(x)=7

    Both are antiderivatives of the specified function; they are members of the family with different constant values.

Answer

Yes.

03 / YOUR TURN

Try it yourself.

Check your understanding

Find ∫3x2d⁢x.

Show answer & reasoning

x3+C

The power rule gives ∫3x2d⁢x=3x33+C=x3+C. Differentiating verifies 3x2; the constant remains undetermined.

Keep practising

6 worksheet questions · 18 marks

Read the questions online
  1. Find ∫4⁢xd⁢x.
    3 marks
  2. Find ∫(9x2+2)d⁢x.
    3 marks
  3. Find ∫(x3−5⁢x)d⁢x.
    3 marks
  4. Find ∫7d⁢x and explain the variable in the answer.
    3 marks
  5. A student claims 3x2 is an antiderivative of 3⁢x. Check and correct the claim.
    3 marks
  6. For f⁡(x)=2⁢x+1, give two different antiderivatives and explain their relationship.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find ∫4⁢xd⁢x.
    3 marks

    Raise the power to 2, then divide 4x2 by 2.

    Add C.

    2x2+C
  2. Find ∫(9x2+2)d⁢x.
    3 marks

    9x2 integrates to 3x3; 2 integrates to 2⁢x.

    3x3+2⁢x+C
  3. Find ∫(x3−5⁢x)d⁢x.
    3 marks

    Integrate each power separately and add C.

    x44−5x22+C
  4. Find ∫7d⁢x and explain the variable in the answer.
    3 marks

    The derivative of 7⁢x is 7; the integral is with respect to x.

    7⁢x+C
  5. A student claims 3x2 is an antiderivative of 3⁢x. Check and correct the claim.
    3 marks

    The derivative of 3x2 is 6⁢x, not 3⁢x.

    Divide by 2 before differentiating back.

    Incorrect; 3x22+C is the family.
  6. For f⁡(x)=2⁢x+1, give two different antiderivatives and explain their relationship.
    3 marks

    Both differentiate to 2⁢x+1.

    They differ by a constant.

    For example x2+x and x2+x+4.
Checking saved progress…
Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 Mathematical Methods integration and logarithmic antiderivatives; original learning and assessment material, with by-hand methods and explicitly described numerical models.

Official curriculum source ↗

Save your next step.

Create a free account to save your learning progress. Lessons and downloads stay free, with or without an account.

Create free account