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YEAR 12 · DIFFERENTIATION AND APPLICATIONS · 18 MIN

Derivatives of sine/cosine/tangent

Differentiate trigonometric functions using radians and the inner rate.

In this lesson

Before you start
  • Trigonometric graphs
  • Chain and product rules
01 / LEARN

Understand the idea.

Radians are part of the rule

For radian inputs, the derivatives of sinx, cosx and tanx are cosx, −sinx and sec2x respectively, with secx=1cosx. A numerical degree input would require an additional conversion factor.

A scaled angle needs the chain rule: dd⁢xsin(k⁢x)=kcos(k⁢x). Keep the same angle inside the trigonometric function; differentiating does not replace k⁢x by x.

Structure and domain

Read the full structure before selecting a rule. A product needs the product rule, while sin2x=(sinx)2 needs the chain rule for an outer square and an inner sine.

Tangent and its derivative require a nonzero cosine. For tanx, exclude x=π2+k⁢π, k∈ℤ; for a composite angle, solve the corresponding cosine-zero condition for the actual input.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Scaled trigonometric angles

Differentiate y=3cos(2⁢x)−sinx.

Worked solution

  1. 1

    Differentiate the cosine term using its inner angle.

    dd⁢x(3cos(2⁢x))=3(−sin(2⁢x))⋅2=−6sin(2⁢x)

    Cosine contributes a negative sine and the angle contributes a factor 2.

  2. 2

    Differentiate the remaining term.

    dd⁢x⁢(−sinx)=−cosx

    The coefficient -1 remains attached to the sine derivative.

  3. 3

    Combine the derivatives.

    y′=−6sin(2⁢x)−cosx

    Differentiation acts term by term on a sum or difference.

Answer

−6sin(2⁢x)−cosx

EXAMPLE 02

A periodic height model

A height is h⁢(t)=2+sin(π⁢t⁢/4) metres. Find its rate at t=0 seconds.

Worked solution

  1. 1

    Differentiate the height model.

    h′(t)=π4cos(π⁢t4)

    The constant height offset has zero derivative; the angle rate is pi/4.

  2. 2

    Substitute the stated time.

    h′(0)=π4cos0=π4

    Cosine is 1 at zero radians.

  3. 3

    Interpret with the correct units.

    h′(0)=π4 ms−1

    The positive rate means height is increasing at the initial instant.

Answer

π4 metres per second

03 / YOUR TURN

Try it yourself.

Check your understanding

Differentiate sin2x.

Show answer & reasoning

2sinxcosx

Treat sin2x as an outer square of sinx. The outer derivative gives 2sinx and the inner derivative gives cosx, so the result is 2sinxcosx.

Keep practising

6 worksheet questions · 13 marks

Read the questions online
  1. Differentiate 5sinx+2cosx.
    2 marks
  2. Differentiate tan(3⁢x).
    2 marks
  3. Find the gradient of y=cos(2⁢x) at x=π4.
    2 marks
  4. Differentiate xsinx.
    2 marks
  5. Differentiate cos3x.
    2 marks
  6. For h⁢(t)=5+2cos(π⁢t6) metres, find and interpret h′(3) in m/s.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Differentiate 5sinx+2cosx.
    2 marks

    Apply the sine and cosine rules term by term.

    5cosx−2sinx
  2. Differentiate tan(3⁢x).
    2 marks

    Use the tangent rule.

    Multiply by 3 from the inner angle.

    3sec2(3⁢x)
  3. Find the gradient of y=cos(2⁢x) at x=π4.
    2 marks

    The derivative is −2sin(2⁢x).

    At π4, the sine is 1.

    −2
  4. Differentiate xsinx.
    2 marks

    Use the product rule.

    Differentiate one factor at a time.

    sinx+xcosx
  5. Differentiate cos3x.
    2 marks

    Differentiate the outer cube.

    Multiply by −sinx.

    −3cos2xsinx
  6. For h⁢(t)=5+2cos(π⁢t6) metres, find and interpret h′(3) in m/s.
    3 marks

    Differentiate to get −(π3)sin(π⁢t6).

    At t=3, the angle is π2.

    −π3 m/s: the height is decreasing.
Checking saved progress…
Curriculum reference & lesson scope

SACE Stage 2 Mathematical Methods

Further differentiation and applications from the current SACE Methods outline. Logarithmic derivatives have their own chapter; integration follows later. Trigonometric calculus uses radians.

Official curriculum source ↗

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