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YEAR 12 · LINEAR MODELS AND OPTIMISATION · 18 MIN

Objective functions

Write the quantity to optimise separately from the constraints and evaluate it with the correct units.

In this lesson

Before you start
  • Linear models
  • Feasible regions
01 / LEARN

Understand the idea.

Define what best means

The objective function measures what the decision should improve. Specify whether to maximise profit, minimise cost or meet another stated aim. Constraints describe what is allowed; they do not by themselves identify the aim.

For profit, subtract each unit cost from its selling price before multiplying by quantity. A fixed cost reduces every plan by the same amount, so it does not change the best feasible mix when the constraints stay the same.

A family of parallel lines

Each equation P=a⁢x+b⁢y with a fixed value of P describes a line. Changing P moves that line parallel to itself. This gives a graphical way to see which feasible boundary is reached by better objective values.

On a non-empty bounded polygon, a linear objective reaches an optimum at a vertex. Compare every feasible vertex. If the objective is constant along a whole feasible edge, all points on that edge tie; an optimum need not be unique.

P=a⁢x+b⁢y
02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Profit rather than revenue

Basic kits sell for AUD 18 and cost AUD 11. Deluxe kits sell for AUD 26 and cost AUD 15. Write profit for x basic and y deluxe kits; evaluate at (6,4).

Worked solution

  1. 1

    Calculate the profit per kit.

    Basic profit=18−11=7Deluxe profit=26−15=11

    Selling prices include the costs that must first be recovered.

  2. 2

    Write the total profit objective.

    P=7⁢x+11⁢y

    Each basic kit contributes AUD 7 and each deluxe kit contributes AUD 11.

  3. 3

    Evaluate the proposed mix.

    P⁢(6,4)=7⁢(6)+11⁢(4)=42+44=86

    Six basic and four deluxe kits produce AUD 86 profit under the stated unit costs.

Answer

P=7⁢x+11⁢y; AUD 86.

EXAMPLE 02

Compare corners

A region has vertices (0,0),(5,0),(3,4),(0,6). Maximise P=4⁢x+5⁢y.

VertexP
(0,0)0
(5,0)20
(3,4)32
(0,6)30

Worked solution

  1. 1

    Evaluate the first two corners.

    P⁢(0,0)=0P⁢(5,0)=4⁢(5)=20

    Substitute each feasible corner into the same objective P=4⁢x+5⁢y.

  2. 2

    Evaluate the remaining corners.

    P⁢(3,4)=4⁢(3)+5⁢(4)=32P⁢(0,6)=5⁢(6)=30

    All four corner values are needed for the comparison.

  3. 3

    Select the largest value.

    max{0,20,32,30}=32

    A linear objective on the given bounded polygon attains a maximum at a vertex; (3,4) has the largest value.

Answer

Maximum 32 at (3,4).

03 / YOUR TURN

Try it yourself.

Check your understanding

Write profit when each x earns AUD 9 and each y earns AUD 4. Evaluate at (2,7).

Show answer & reasoning

P=9⁢x+4⁢y; AUD 46.

The profit objective is P=9⁢x+4⁢y. At (2,7) it gives 9⁢(2)+4⁢(7)=18+28=46, so the profit is AUD 46.

Keep practising

6 worksheet questions · 12 marks

Read the questions online
  1. A has unit revenue 35 and cost 23; B has revenue 28 and cost 19. Write profit.
    2 marks
  2. Evaluate C=8⁢x+13⁢y at (4,3).
    2 marks
  3. At vertices (0,0),(8,0),(4,5),(0,7), maximise P=3⁢x+4⁢y.
    2 marks
  4. At vertices (2,3),(7,3),(4,6), minimise C=5⁢x+2⁢y.
    2 marks
  5. Does subtracting a fixed AUD 100 change the maximiser of P=7⁢x+5⁢y?
    2 marks
  6. Why does every point from (0,6) to (6,0) have the same P=2⁢x+2⁢y?
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. A has unit revenue 35 and cost 23; B has revenue 28 and cost 19. Write profit.
    2 marks

    Subtract each unit cost from revenue first.

    P=12⁢x+9⁢y.
  2. Evaluate C=8⁢x+13⁢y at (4,3).
    2 marks

    32+39=71.

    71.
  3. At vertices (0,0),(8,0),(4,5),(0,7), maximise P=3⁢x+4⁢y.
    2 marks

    The values are 0,24,32,28.

    Maximum 32 at (4,5).
  4. At vertices (2,3),(7,3),(4,6), minimise C=5⁢x+2⁢y.
    2 marks

    The values are 16,41,32.

    Minimum 16 at (2,3).
  5. Does subtracting a fixed AUD 100 change the maximiser of P=7⁢x+5⁢y?
    2 marks

    All objective values decrease equally, preserving their order.

    No, if the feasible set stays unchanged.
  6. Why does every point from (0,6) to (6,0) have the same P=2⁢x+2⁢y?
    2 marks

    On that edge x+y=6, so P=2⁢(x+y)=12.

    Each has P=12.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 General Mathematics: Modelling with Linear Relationships, a compulsory school-assessed topic. The external examination scope differs from the full course.

Official curriculum source ↗

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