Understand the idea.
Choose the unknown before entering numbers
Start with the balance equation and identify the unknown. If the target is and initial savings are , those savings contribute at the target date. Only the remaining gap must be supplied by the regular deposits.
For end-of-period deposits, divide that gap by the savings-annuity factor to find . A negative result means the initial savings alone exceed the target under these assumptions; it does not describe a required positive deposit.
Whole periods and numerical solutions
A solver may return a fractional number of periods, but deposits occur at specified dates. To find the first whole period reaching a target, test the next integer and the preceding integer. Rounding to the nearest integer can leave a shortfall.
An unknown rate appears both inside the power and in the annuity denominator. Solve the full equation numerically over a stated valid interval, then substitute the result back. Keep the rate, deposit timing and initial balance consistent throughout the calculation.
See the method in action.
Build the model
What equal year-end deposit reaches AUD 10,000 after 8 years at 4% annually, starting from zero?
Worked solution
- 1
Model eight equal year-end deposits from zero.
The eighth deposit is made at the target date and receives no interest.
- 2
Isolate the regular deposit.
Dividing by the accumulated value of one unit per year gives the required deposit.
- 3
State the deposit to cents.
The exact model value is rounded only after solving the equation.
AUD 1,085.28
Use the model to make a decision
Starting from zero, deposit AUD 500 at each year end at 5%. Find the first whole year when the balance reaches AUD 4,000.
Worked solution
- 1
Express the target as an inequality.
The first qualifying year must reach or exceed the target after its deposit.
- 2
Solve the boundary equation.
Taking logarithms finds the continuous threshold; actual deposits occur only at whole years.
- 3
Check the adjacent whole years.
Six deposits fall short, while seven deposits exceed AUD 4,000.
- 4
Choose the first qualifying deposit date.
With positive deposits and interest, these balances increase each year, so no earlier year reaches the target.
7 years
Try it yourself.
Check your understanding
With no interest, what monthly deposit reaches AUD 2,400 after 16 months?
Show answer & reasoning
AUD 150.00
With no interest, the 16 deposits must sum to AUD 2,400. Thus and , giving AUD 150.00 per month.
Keep practising
6 worksheet questions · 18 marks
Read the questions online
- AUD 3,000 is already saved. What year-end deposit reaches AUD 12,000 in 5 years at 4%?3 marks
- With no interest, what monthly deposit reaches AUD 2,400 after 16 months?3 marks
- A person can deposit AUD 250 at each year end for 6 years. At 3%, how much initial savings are needed to reach AUD 8,000?3 marks
- Find the annual rate between 0 and 10% for which five end-of-year deposits of AUD 1,000 accumulate to AUD 5,500.3 marks
- A solver gives annual deposits to reach a target. How many whole deposits are needed, and what check should be made?3 marks
- At 4% annually for 10 years, compare the end-of-year and beginning-of-year deposits needed to reach AUD 20,000.3 marks
Read the worked solutions
Equivalent correct methods earn the corresponding marks. Include units where asked.
- AUD 3,000 is already saved. What year-end deposit reaches AUD 12,000 in 5 years at 4%?3 marks
Grow the initial AUD 3,000 for 5 years.
The deposits must supply .
Divide this by the five-period annuity factor.
AUD 1,541.64 - With no interest, what monthly deposit reaches AUD 2,400 after 16 months?3 marks
At zero interest, .
.
AUD 150.00 - A person can deposit AUD 250 at each year end for 6 years. At 3%, how much initial savings are needed to reach AUD 8,000?3 marks
The deposits contribute .
Subtract that from 8000, then discount the remainder by .
AUD 5,345.58 - Find the annual rate between 0 and 10% for which five end-of-year deposits of AUD 1,000 accumulate to AUD 5,500.3 marks
Solve numerically, using the zero-rate limit at .
A root search gives .
Substitution gives a final balance of AUD 5,500.
4.7673% - A solver gives annual deposits to reach a target. How many whole deposits are needed, and what check should be made?3 marks
The goal is not achieved after only 9 complete deposits.
Round upwards and verify the crossing, rather than rounding to the nearest integer.
10 deposits; calculate balances after 9 and 10 deposits. - At 4% annually for 10 years, compare the end-of-year and beginning-of-year deposits needed to reach AUD 20,000.3 marks
The beginning-deposit annuity factor is 1.04 times the ordinary factor.
Divide the same target by each factor.
Beginning deposits can be smaller because they earn longer.
End: AUD 1,665.82; beginning: AUD 1,601.75.
Curriculum reference & lesson scope
SACE Board of South Australia
Stage 2 General Mathematics financial models: investments and annuities, superannuation, income streams and borrowing. Original practice uses supplied hypothetical rates, taxes and fees; statutory or commercial conditions are not inferred.
Official curriculum source ↗