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YEAR 11 · STATISTICS · 18 MIN

Outliers and fair conclusions

Investigate unusual observations without hiding genuine extremes.

In this lesson

Before you start
  • Quartiles and distribution shape
01 / LEARN

Understand the idea.

A flag starts an investigation

The 1.5⁢I⁢Q⁢R rule flags a value below Q1−1.5⁢I⁢Q⁢R or above Q3+1.5⁢I⁢Q⁢R. Calculate the quartiles using the stated convention. Values equal to a fence are not outside it.

A flag identifies distance from the central data; it does not diagnose an error. Check the original response, units and intended population. A genuine long journey may be important evidence about the group.

Show sensitivity honestly

Correct verified recording errors and document the evidence. Use a defensible, stated exclusion rule when one applies. Do not remove a valid observation simply because it changes the conclusion or makes an average less attractive.

A sensitivity analysis shows results with and without a questionable extreme, explaining the distinction. Mean and range can shift sharply while median or IQR change less. Both calculations describe different sets of observations and must be labelled.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Find fences

Q1=10, Q3=18. Test−3 and 31.

Worked solution

  1. 1

    Calculate the IQR.

    I⁢Q⁢R=18−10=8

    The central spread determines the distance used beyond each quartile.

  2. 2

    Calculate both fences.

    L=10−1.5⁢(8)=−2U=18+1.5⁢(8)=30

    The rule extends one and a half IQRs below and above the central half.

  3. 3

    Compare each value with the fences.

    −3<−2,31>30

    Both values lie strictly outside the permitted fence interval.

  4. 4

    State the appropriate response.

    Flag both observations for checking; neither comparison proves that the recorded value is wrong.

Answer

Both flagged; neither automatically wrong.

EXAMPLE 02

Sensitivity

Compare 4, 5, 5, 6, 30 with and without 30.

Worked solution

  1. 1

    Summarise all five values.

    x¯=4+5+5+6+305=10,median=5

    The full data total fifty, and the third ordered value is five.

  2. 2

    Summarise the four values without thirty.

    x¯=4+5+5+64=5,median=5+52=5

    Removing one value changes both the total and the count.

  3. 3

    Compare the sensitivity.

    10−5=5

    The mean drops by five while the median is unchanged, showing that the high value strongly affects the mean.

  4. 4

    Separate the calculation from the decision.

    A lower mean is not itself a valid reason to exclude thirty; any exclusion needs evidence or a defensible rule.

Answer

Exclusion changes mean 10 to 5 but still needs a valid reason.

03 / YOUR TURN

Try it yourself.

Check your understanding

Q1=6, Q3=10. Upper fence?

Show answer & reasoning

16.

First find I⁢Q⁢R=10−6=4. The upper fence is Q3+1.5⁢I⁢Q⁢R=10+1.5⁢(4)=16. It begins at the upper quartile, not at the median.

Keep practising

6 worksheet questions · 12 marks

Read the questions online
  1. Find fences for Q1=12, Q3=20.
    2 marks
  2. A value equals the upper fence 32. Is it flagged by the strict outside rule?
    2 marks
  3. Source confirms 1.75 m entered as 1.75 cm. What correction?
    2 marks
  4. Find mean and median of 3, 4, 4, 5, 24.
    2 marks
  5. Slow runners are removed to improve mean race time. Explain the problem.
    2 marks
  6. Results change greatly without one genuine extreme. What should be reported?
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find fences for Q1=12, Q3=20.
    2 marks

    IQR 8; subtract/add 12.

    0 and 32.
  2. A value equals the upper fence 32. Is it flagged by the strict outside rule?
    2 marks

    The rule uses values above, not equal to, the fence.

    No.
  3. Source confirms 1.75 m entered as 1.75 cm. What correction?
    2 marks

    It is a verified unit mismatch.

    175 cm, documenting the unit correction.
  4. Find mean and median of 3, 4, 4, 5, 24.
    2 marks

    Total 40 divided by count 5; third value 4.

    Mean 8; median 4.
  5. Slow runners are removed to improve mean race time. Explain the problem.
    2 marks

    Exclusion cannot be justified by wanting a nicer result.

    Selective removal of genuine outcomes biases the description.
  6. Results change greatly without one genuine extreme. What should be reported?
    2 marks

    Readers need to see the sensitivity.

    Both relevant results, the treatment rule and a cautious conclusion.
Checking saved progress…
Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 General Mathematics: statistical investigation, univariate data, sampling, displays, summaries and interpretation.

Official curriculum source ↗

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