One-/two-digit problems

Worked solution

1. 1

   Write the equal-group calculation.

   $3\times 16$

   There are three rows and sixteen plants in every row.

2. 2

   Split each row into ten and six plants.

   $16=10+6$

   This split includes all sixteen plants in each row.

3. 3

   Count each part across three rows.

   $\begin{array}{rl}3\times 10& =30\\ 3\times 6& =18\end{array}$

   The ten-plant and six-plant parts are each repeated three times.

4. 4

   Add the plant totals.

   $30+18=48$

   The garden contains forty-eight plants altogether.

Worked solution

1. 1

   Find the largest possible number of full pots.

   $6\times 4=247\times 4=28$

   Six pots use no more than twenty-seven pencils, but seven full pots need too many.

2. 2

   Find the pencils not used in full pots.

   $27-24=3$

   Six full pots use twenty-four of the twenty-seven pencils.

3. 3

   Check the grouping and leftover.

   $6\times 4+3=273<4$

   The three remaining pencils cannot fill another pot, so there are six full pots and three left.