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YEAR 6 · NUMBER PROPERTIES AND CALCULATIONS · 10 MIN

Efficient calculation and estimation

Choose efficient whole-number strategies and use estimates to check the result.

In this lesson

Before you start
  • Place value
  • Four operations with whole numbers
01 / LEARN

Understand the idea.

Change the calculation without changing its value

Compensation replaces an awkward number with a nearby convenient one, then corrects the change. If you replace 398 by 400 in an addition, you have added 2 too much and must subtract 2 from the result.

Regrouping factors can also help. For 25×16, write 16=4×4 and combine 25×4 first. The factors still represent the same product, but the intermediate calculation becomes 100×4.

Estimate before trusting an answer

An estimate uses easy nearby numbers to check the size of an answer. Mark it as approximate. A close estimate supports a calculation, but does not prove that every digit of the exact answer is correct.

Check what the context requires as well as the arithmetic. If some passengers remain after filling several buses, another whole bus is needed. Rounding a quotient down would leave those passengers without seats.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Worked example 1

Calculate 599+286 efficiently.

Worked solution

  1. 1

    Make the first addend easier.

    600+286=886

    Replacing 599 by 600 adds one extra unit.

  2. 2

    Compensate for the extra unit.

    599+286=886−1=885

    Subtracting the added unit restores the original total.

  3. 3

    Check the size.

    600+300=900

    The exact answer 885 is slightly below this rounded estimate, as expected.

Answer

885.

EXAMPLE 02

Worked example 2

A school buys 18 boxes of 24 pencils. Find the total and check it.

Worked solution

  1. 1

    Calculate the total for 20 boxes.

    20×24=480

    Twenty boxes give an easy nearby calculation.

  2. 2

    Find the pencils in the two extra boxes.

    2×24=48

    Eighteen boxes are two fewer than twenty.

  3. 3

    Remove those extra pencils.

    18×24=480−48=432

    The subtraction leaves exactly the pencils in 18 boxes.

  4. 4

    Check and label the result.

    20×20=400

    An estimate of about 400 agrees with the size of 432 pencils.

Answer

432 pencils.

03 / YOUR TURN

Try it yourself.

Check your understanding

Choose a sensible estimate for 198×31: 600, 6,000 or 60,000.

Show answer & reasoning

6,000.

Round to 200×30=6.000. This is close to the original calculation, so 6.000 is the sensible estimate.

Keep practising

6 worksheet questions · 12 marks

Read the questions online
  1. Use compensation to calculate 497+358.
    2 marks
  2. Calculate 25×28 by making a factor of 100.
    2 marks
  3. Calculate 1,002−498 efficiently.
    2 marks
  4. Estimate 61×39 using convenient tens.
    1 mark
  5. A calculator shows 7,200 for 48×15. Explain why this is unreasonable, then correct it.
    3 marks
  6. A club has 178 people. Each bus seats 40. How many buses are needed?
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Use compensation to calculate 497+358.
    2 marks

    500+358−3=855.

    855.
  2. Calculate 25×28 by making a factor of 100.
    2 marks

    25×4×7=100×7=700.

    700.
  3. Calculate 1,002−498 efficiently.
    2 marks

    1,002−500+2=504.

    504.
  4. Estimate 61×39 using convenient tens.
    1 mark

    60×40=2,400.

    About 2,400.
  5. A calculator shows 7,200 for 48×15. Explain why this is unreasonable, then correct it.
    3 marks

    50×15 is about 750. Exactly, 48×10+48×5=480+240=720.

    It is about ten times too large; the correct answer is 720.
  6. A club has 178 people. Each bus seats 40. How many buses are needed?
    2 marks

    Four seat 160, leaving 18 people, so one more is needed.

    5 buses.
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Curriculum reference & lesson scope

Australian Curriculum v9 and SA Curriculum Mathematics

Prime/composite/square numbers; factors/multiples revision; efficient calculation and estimation.

Official curriculum source ↗

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