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YEAR 6 · FRACTIONS · 10 MIN

Addition/subtraction

Add and subtract fractions by first making the pieces the same size.

In this lesson

Before you start
  • Equivalent fractions
  • Common multiples
01 / LEARN

Understand the idea.

Make the pieces match

Addition and subtraction combine counts of the same kind of piece. Rename unlike fractions with a common denominator first. For thirds and quarters, twelfths let you count all the pieces using a single unit.

Once the pieces match, add or subtract only the numerators. In 412+312=712, the answer is still measured in twelfths. Adding denominators would invent a different piece size instead of combining the given amounts.

Simplify and check

Convert a mixed number to an improper fraction when that makes subtraction clearer. Count the parts in the whole number as well as the fractional part. Then rename both fractions, calculate, and simplify if a common factor remains.

Check the result’s size. Adding a positive fraction must increase the starting value; subtracting one must decrease it. A numerator at least as large as its denominator represents at least one whole and may be written as a mixed number.

02 / WORKED EXAMPLES

See the method in action.

EXAMPLE 01

Worked example 1

Calculate 23+14.

Worked solution

  1. 1

    Rename both fractions in twelfths.

    23=812,14=312

    Twelve is a common multiple of both denominators.

  2. 2

    Add the counts of twelfths.

    812+312=8+312=1112

    The pieces stay the same size while their counts are added.

  3. 3

    Check the answer’s size and form.

    23<1112<1

    The sum is greater than the starting fraction and has no common factor to simplify.

Answer

1112.

EXAMPLE 02

Worked example 2

Calculate 1⁤14−23.

Worked solution

  1. 1

    Convert the mixed number.

    1⁤14=44+14=54

    The whole contributes four quarters.

  2. 2

    Rename both amounts in twelfths.

    54=1512,23=812

    A common denominator makes the parts suitable for subtraction.

  3. 3

    Subtract the counts.

    1512−812=712

    Taking away eight of the fifteen twelfths leaves seven.

  4. 4

    Check by adding back.

    712+812=1512=1⁤14

    Restoring the subtracted amount gives the original value.

Answer

712.

03 / YOUR TURN

Try it yourself.

Check your understanding

Calculate 56−13.

Show answer & reasoning

12.

13=26, so 56−26=36=12. Three of the six equal parts make half the whole.

Keep practising

6 worksheet questions · 11 marks

Read the questions online
  1. Calculate 38+18.
    1 mark
  2. Calculate 12+15.
    2 marks
  3. Calculate 56−14.
    2 marks
  4. Calculate 34+23.
    2 marks
  5. Calculate 2−35.
    2 marks
  6. A ribbon is 78 metre long. A 14 metre piece is removed. What remains?
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Calculate 38+18.
    1 mark

    48 simplifies to 12.

    12.
  2. Calculate 12+15.
    2 marks

    510+210=710.

    710.
  3. Calculate 56−14.
    2 marks

    1012−312=712.

    712.
  4. Calculate 34+23.
    2 marks

    912+812=1712.

    1712=1⁤512.
  5. Calculate 2−35.
    2 marks

    2=105; 105−35=75.

    1⁤25.
  6. A ribbon is 78 metre long. A 14 metre piece is removed. What remains?
    2 marks

    14=28; 78−28=58.

    58 metre.
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Curriculum reference & lesson scope

Australian Curriculum v9 and SA Curriculum Mathematics

Equivalence; comparing/ordering; addition/subtraction; practical quantities.

Official curriculum source ↗

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